# Hey Logic Decoders: Can You Solve This Ted-Ed Fish Riddle?

Submitted by: fancylad 1 year ago in
7

Pay attention, there's a lot of information in the set up.
7
Male 13,271
We're all wrong. At 29 seconds you can clearly see there are 11 tanks on the boat. ;)
Male 4,484
So here's how I solved it:
50 creatures - 6 sharks = 44 creatures in the 3 sections
Section 3 can have 1, 3, 5, 6, or 7 sharks in it.
44 - 1 = 43
43 is prime, so, that's not right
44 - 3 = 41
41 is prime
44 - 5 = 39
39 is not prime
What's the first number that's divisible into 39 (excluding 1)
3
39 / 3 = 13
All the variables fit the requirements.

5 sharks (in Gamma)
3 fish per tank
13 tanks (7 tanks in Gamma)
Male 10,128
Set up a spreadsheet and go the same result.   Actually, there are two (2) valid results that equal 50 total organisms, except it results in the same number of sharks in Gamma, so can be discounted.

Male 161
The really clever bit was using thermal imaging to find fish in water .. how did they do that? Thermal imaging doesn't work through water, never mind seeing cold blooded animals that are the same temperature as their surroundings.
Female 6,692

Math.. noooope.  Shit goes extinct every day, fuck 'em this will make for healthier sharks.
-1
Male 9,488
Male 2,194
Oh man, this solution was SO MUCH MORE ELEGANT than mine!!!

I worked out how many sharks there would be for every single permutation of 1, 2, 3, 4, 5, 6, 7, 8 fish, and so on, and then crossed out all of the answers where the number of sharks in gamma was the same number of sharks in either of alpha or beta.

Man, I did so much extra work...
Male 9,488
Congratulations Layla, HG, and BUN1! You three are smart. I was feeling lazy and didn't stop the video before the solution. *shame*
Male 192
man I did this completely different
I worked with "they say no more than 13 so let's assume there are 13 total"
then 6f+6s=12t+7fg=19t 31 is too many sharks
12f+6s=28t+14fg=42t 8 is too many sharks
18f+6s=24t+21fg=45 5 sharks fit
guess I got lucky
Male 13,271
f= Fish in Tanks
T= Tanks in sector Gamma
S= Sharks in sector Gamma

(4f+2)+(2f+4)+(Tf+S) = 50
(6+T)f = 44-S

S = 1,3,5,6,7
T = 0,1,2,3,4,5,6,7
f = 1,2,3,4,5,6,7

(1 Shark ) (6+T)f = 43
(3 Sharks) (6+T)f = 41
(5 Sharks) (6+T)f = 39
(6 Sharks) (6+T)f = 38
(7 Sharks) (6+T)f = 37

f =/= 1
f =/= 2
f = 3 works for 39 (5 Sharks)
f =/= 4
f =/= 5
f =/= 6
f =/= 7

(6+7)3= 44-5

7 Tanks in sector Gamma
5 Sharks in sector Gamma
3 fish in each tank

1,097
5 Sharks, 7 Tanks, 3 fish in each tank

2+4+5 = 11 sharks, 2+4+7  = 13 tanks, 13 x 3 = 39. 39+11 = 50.
Male 877
Jesus... what is wrong with this boat?