As a guess, I`d assume it`s 60%. It can`t be 25% as two of the answers are the same and it can`t be 50% as the other two answers are different. 60% is the only answer left so it must be that.

Normally in 4 answer questions, you have a 25% chance of getting it right. However, because two of the answers is 25% then that answer becomes void.

So A and D are not the correct answer. You only have a 25% chance of choosing B and a 25% of choosing C. However, 50% is not the correct answer, and neither is 60%.

So you might think, "Oh, there is no correct answer listed here. So the answer must be 0%". And you`d be right. However, listing 0% as an option would change the answer to the question. As such, the possibility of guessing 0% would be more than 0%.

It`s a trick question with no answer. (But really the answer is 0%, unless the option of 0% is given).

The answer is cyclical so there is no answer: Normally a random choice would provide 25% (1 in 4). Since there are two answers that are 25% your chance of selecting one of them is 50%. Therefore your answer is B. So you have a 25% chance of selecting B, so your answer is A or D which gives you a 50% of being right so your answer is B -> and on and on we go....

4 answers = 25% the avarage results of guessing is roughly 50% if you have a slight idea about said question, it is raised to 60% then you take a probability calculator, give it a nice cup of hot tea. and This is the defining factor. so the percentage becomes irrelevant becuase you are alway`s right. normality is now restored, anything you can`t cope with is therefore your own problem.

MrOrange, we gotta stop meeting on oposite sides of topics.

Answer - it`s a trick question. You`d think 1 in 4 is 25% but A & D are 25% so that makes it 2 in 4 which is 50%. But B is 50% so we`re back to 1 in 4 or 25%.

The validity of the question depends upon the type of random distribution involved, answer selection method and the person selecting the answer.

inb4 paradox: Not necessarily. It`s only a 25% of picking a correct answer if you assume true randomness to your distribution, so unless the answer is being picked by a process involving radioactive decay it is not truly random.

it is a trick question yess, but not a percentage one. This question, that excludes averages. The answers provided can be correct or can`t be. it`s your own insecurity that tells you that it can`t be and that there has to be a correct answer in which case you enter the paradox. you are alway`s right. becuase there is no evidence to suggest you are wrong.

oh and Gerry1of1, if you look at yourself in a mirror, how many of you are there?

Actually, it never enters the infinite logic loop, most people would say that it`s first 25% because there are 4 possibilities, but 2 of them are the same, so IF the correct answer was 25% then there is a 50% chance of choosing the right one, BUT we have no reason to initially assume 25% as it does not fit the situation of 4 different answers. Therefore, because we don`t know that the answer is 25%, we also can`t then assume the answer to become 50%. Instead, we can look at all the different possibilities and consider them to be equally likely to be the initial answer. If it`s 25%, there`s a 50% chance of getting the right answer, if it`s 50% you have a 25% chance, and if it`s 60% you also have a 25% chance of getting it right. So as stated, if we consider that initially each of them is equally likely, the we get that each value (25%, 50%, or 60%) has a 33% chance of being the right answer. So the probability of guessing (at random) the correct answer is: (1/2 + 1/4 + 1/4)*(1/3)

You`d think 1 in 4 is 25% but A & D are 25% so that makes it 2 in 4 which is 50%. But B is 50% so we`re back to 1 in 4 or 25%. Dammit you are right. I had this whole retort ready but it kept falling apart.

The answer is 0. Since two answers are the same, this gives you three possible answers to the question. Since none of the answers is 33.33% then you have a 0 percent chance of getting this right.

So we have that the probability is 33%, if you were to re-evaluate the question with the probability of guessing this, you would see that the probability is 0, and the probability of guessing that is 0, and so on....

0% You will always be wrong... not because the question doesn`t have an answer. Just because you`re a failure. Now drop your math class and go take gym again.

The answer depends on whether or not A and D are both considered correct, or if you have to choose a predetermined answer of A or D despite them being identical. If it`s the first case, then the answer is B. If it`s the second case, then the answer is either A or D.

To make this easier, let`s just say that both A and D are considered correct, so the answer is B, 50%. Why? What`s the probability of choosing the correct answer out of 4 options? 25%. Consider that 25% shows up twice, so the answer has to be 50%, because you have a 50% chance of choosing either of the 25%`s.

No, Orange, it`s not insecurity on my part. If the question is the odds of getting it right, and the answer to that is zero, but zero is not an option, then it`s a trick question.

To answer your question - How many of "me" in the mirror... None, I`m a vampire.

@gerry1of1 if the answers provided to the question are not correct, it means you can`t answer the question with those answers so if i say that my answer is right, the answers provided can`t be used to say i am wrong becuase they are. hence i am right.

as long as you think that there is a right answer among the wrong answers you will be wrong.

if i look in a mirror, i can see two of me, but i know there is only one of me.

if take the sentence apart, This question, that excludes others so averages do not count. "if you choose an answer at random" where does it say that i have to pick one of the below?

and that my opposing friend is the trick in the question.

There is nothing wrong with the above statement, you could only say that it is wrong becuase it claims to be true _until_ it is proofed _wrong_, which alows you to think it can be wrong but you can`t prove it is wrong hence it is alway`s true.

it`s a linguistic paradox which holds no meaning other then what you give it. if you think it can be wrong, you will search in vain for that argument and you enter the paradox, accept that it is true and you do not.

The answer is 25%.. one of the 25%s would be correct, but not both. This of course is with the assumption that it is a multiple choice question with only 1 answer allowed, the correct 1 answer, and 4 exclusive choices... thus removing answers where you can bubble in multiple choices. With that assumption there is no paradox... A person randomly bubbling it in would have a 1 in 4 chance always... you as the non-guesser have a 50% chance of picking the correct 25%.. but that`s not the question posed.

MrOrange "and that my opposing friend is the trick in the question." Told`ya it was a trick question. But it`s taken you 4 posts and a dozen paragraphs proving me wrong before you agreed with my conclusion.

The answer can never be B, or C. There is only 1 correct answer and 4 choices, 2 25%s choices are still individual answers.. the person picking at random will ONLY pick 1 answer.. and ONLY has a 25% chance.... 1 of the 4 answer is correct, not 2. The trickery is for you the person reading and not picking picking at random.

Randomly means not applying logic, selecting one of 4.

Without consideration to the answers provided and selecting randomly, the correct answer is 25%.

Since this test cheats and offers the 25% value twice, the answer may seem as though it would be 50%. If it were 50%, then the odds of picking 50% are 25% STILL.

So 25% is there twice, 50% chance of picking 25%, plus the chance of picking 50%, which makes 3 of the answers correct.

75% chance of picking A right answer, which is not on the test, therefore the odds of finding the correct answer of 75% is non existant, and thus the correct answer is 0%!

NEVER GO IN AGAINST A SCICILIAN, WHEN DEATH IS ON THE LINE! Hahaha, hahaha, haha.....*dead*

my reasons, the human mind there is a greater probability that when someone doesnt know a multiple choice answer they go for C. or will go for one of the middle answers

very very rarely do people pick the 2 outer answers.

theere is a very old psychological trick where if u ask someone to just think of a number between 1-10 60% of people will pick the number 7. people tend to think the outer edge answers are too obvious so in trying not to fit in with the "regular" people they go for what they beleive to be an obscure number when in actual fact they are following the crowd they so desperatly want to get away from.

to sum up mathematically its either A or D - 25% but psychologically its more like C- 60%

@tedgp, by that logic all probability can be simplified to 50%.

Chance of rain in the Sahara desert...50% Chance you`ll die being struck by a meteor...50% Chance you`ll be impregnated by an extra-terrestrial and give birth to a child who will become the President in 50 years...50%

the chance of choosing the right answer is 25%, there are two correct answers which brings you up to a chance of 50% so the answer to the question is B

Nope, the answer wanted is what is the chance of picking the right answer,

the probability that you pick the right answer is 1/4, so the answer is 25% since there are two correct answers the chance is 50%

thats the probabilty side of it, otherwise you come to the philosophical side of it which bring you to my previous post but appearantly they are to long.

MrOrange-"the probability that you pick the right answer is 1/4, so the answer is 25% since there are two correct answers the chance is 50%"

Take that one more step: The probability that you pick the right answer is 1/4, so the answer is 25% since there are two correct answers the chance is 50%. But the correct answer of 50% only appears once (i.e. 25% of the time) so the correct answer is 25%, but the correct answer of 25% appears twice (i.e. 50% of the time) so the correct answer is 50%, but the correct answer of....Ad infinitum.

Correct answer: "The chance you are correct is 0% Reason: *When choosing answer A, you assume 25% to be correct. This means B and C are not correct and D is correct too. Thus, the correct answer would be 50%. This means A is not a correct answer *Same logic applies to answer D. This means D is not a correct answer. *When choosing answer B, you assume 50% to be correct. This means A,C and D are not correct. Thus the correct answer would be 25%. This means B is not a correct answer. *When choosing answer C, you assume 60% to be correct. This means A, B and D are not correct. Thus the correct answer would be 25% This means C is not a correct answer. ** In summary none of the answers is correct. So the chance you will be correct is 4* 1/4 * 0 = 0%

JUST A QUESTION OF LOGIC

THIS POst should not be on IAB, as it isn`t boring at all!!

well yeah, all arguments about it being 25% are correct, but then if that is indeed the right answer, then it`s not random choice anymore because there are 2 clearly labeled as "25%"

So even though the probability is 25%, the answer is any of the 4

You guys over-think this shyt. There are four possibles. Two of which are 25%. If you put all four answers in a hat and drew one at RANDOM, you will have a 50% chance of pulling out 25%. The answer is B)

Take one step less. "if you choose an answer at random" leads you to 1/4 or 25%. "what is the _chance_ of picking the right answer" since 25% percent is present twice, it`s a 50% chance of picking the right answer at random.

As said before the trick is not in the mathmatics, but in the linquistics.

The correct answer is a 1 in 3 chance of being correct. You don`t actually know the question being asked (you are being asked what the probability of being correct is, not which of those answers is correct to the question), and you really only have three answers (D is thrown in to be confusing, as is the wording of the question). The question is not pick A,B,C, or D, but to assess the probability of being correct in picking an answer.

my grammer and spelling suck so i just googled it, but, what is the function of the comma in grammer? if this definition is "Use a comma to separate the elements in a series (three or more things)"

then do we get closer to reaching an understanding of the question asked?

if we can agree on the question asked then we could perhaps also agree on a solution.

It`s B no matter what. The chance of getting it correct at random is 50% no matter what you do. Because the correct answer to the question is actually 25% (two chances out of 4), the chance of getting that answer is 50%. Just because answer B is correct to answer the question doesn`t mean it`s answering the same question. Essentially, it`s TWO questions with two answers. If the question was the chances of getting one of four answers correctly, it would be 25%. However, it`s REALLY asking what the chances are of getting 2 answers correctly.

@gerry1of1 See what i mean with: The answers provided can be correct or can`t be. it`s your own insecurity that tells you that it can`t be and that there has to be a correct answer in which case you enter the paradox. you are alway`s right. becuase there is no evidence to suggest you are wrong.

there is an probability and a chance of a right answer, and a probabilty of a wrong answer, the question can be answered in more way`s then 1, both on the linguistic side and on the mathmetical side, which means that there is a probability of a right answer, the chances of being proved wrong are irrelevant.

if we each build the exact same wooden house, and we need calculate our sawcut, you could work out the probability of bieng wrong. i could assume i was right, err, on the positive side, make my cut, if lucky it fits if not i cut again, but my house will be ready, whilst your paradoxal excursions

well if you choose to answer or not thats 1/2 and the correct answer would be 25% but a and d are the correct answer so thats also 1/2. so its 1/2*1/2 and the answer is 25%

From my perspective, if i were to choose an answer i knew was wrong at random, that would leave me with B or C and since that would make B correct, the obvious choice is C!

no, the answer is 0% but for different reasons. You have 50% chance to pick 25% you have 25% chance to pick 50% you have 25% chance to pick 60% The correct answer must be the one in which your % chance of picking it matches its declared value. None of those answers match the actual % chance you have to pick an answer, hence the answer is 0.

If you think this is bad googol the "Montey Hall Problem". Given 3 choices (doors) you pick a door at random. The host of the show then opens one of the 2 remaining doors, always the one without the prize. Should you keep your 1st guess or change it to the other closed door? Mathematically it comes down to: When you change your guess instead of keeping the 1st guess you are more likely to obtain the prize. (by some fration of three, I think. I don`t know. Look it up.) So, one random guess becomes less likely when one un-prized is opened. The door not yet considered is more likely than your first random guess. Given no information, of course, all your guesses will random; some more random than others. Check it out, I probably missed an important point.

Oh yeah - The numbers might be the statistics on how often each letter is the answer in real multiple choice. If you don`t know the answer, pick C; if it`s definitely not C then pick B. It might have something to do with teachers trying to "hide" the answer; putting far from the top, but not the bottom. or whatever. I`m guessin`.

B)50%, only 1 answer is possible of 4 choices, because of this fact, no matter what, the chances of choosing the correct answer is 25%, assuming the correct answer is present. That answers the question to ask yourself, but given that there are 2 chances to get 25% in the question you double the value of your odds, that answers the question they ask and the answer is B)50%

but, the question shows you the 2 answers to mess with people. so far from reading the comments people say it`s a paradox that the answer remains 25% just because it`s the only choice, but given that the answer is on the board and the answer is 2/4 answers theres a 50% chance and no need to go further, that answers the question the question raises on what are the chances of being right.

It`s not exactly 50% either. If you say that the right answer is 25% than there are two possible correct answers out of for so 50% is right. But then that means there`s only one correct answer which puts you back to 25% percent being the answer you want. so......

The answer is *UNDEFINED*. Zero is a definate answer, but quite simply one cannot know what the "question" is.

This is not a question that can be answered. Ignore the multiple choices - nothing in the prompt limits you to these four choices. The question has no answer that can be determined with logic.

This is non-sensical. It is not even a paradox. It is like asking "How many flerpas do dipady triznos?" *UNDEFINED*

I think this is a discrete math problem. It doesn`t matter that there are 2 answers that are the same. It matters that there are 4 possible choices but only one guess. In this case, since you have only one guess but 4 choices your answer is 25%. Most would think that since you have 2 25% choices it would be 25% "and" 25% giving you 50% but actually since you only have once choice, the operator isn`t "and" but "or". So the correct answer is "A" or "D" but not "A And D" falsely giving you "B".

Why do you assume that? What in the question limits your choices to those listed? Everyone is conditioned to see A, B, C, D and assume one is the answer. That is the mistake. You are all reading too much into it - I did it to. "Well, if I choose A, there are two so its 50%, so can`t be A, or D, or, um, B...hmmm."

The multiple choice selections are irrelevant and meaningless - again, why only choose those? - tricking you into looking for meaning in them.

See, there actually is no "question." This is more philosophical than logical. What is the right answer? There COULD be a "question" in the mind of the author, and there is some small chance you could randomly choose the answer from the ether, but you simply cannot deduce the probability based on the information given.

What limits you to only those four choices? Too many assumptions that the answer is in front of you. It doesn`t say "choose from below," or "choose from one of these."

It is a trick. You cannot answer the question - thus the answer cannot be 0%, because that is a certain answer. The answer is undefined. Even if there is a correct answer, it is unknowable.

The question is broken into parts, part 1 if you choose AN answer at to this question at random, what is the chance you would be correct. Now, ignoring the answers themselves and looking at possibilities one must ask self, self what do I think is correct? so I look and get 1/4 and get 25% which is correct considering there are 4 choices thus, 25%=correct answer. Part 2 there are 2, 25% choices. 25% is correct for the question, now using a chance to rethink the question, What is the chance you will be correct? knowing that 25%=correct answer, there are two choices that are 25%=correct making the odds 2/4 reducing to 1/2=50% which is the answer to the question because 25% is correct.

I only replied assuming the correct answer is on the board to make things easier to understand, I never said it was, I just assumed that because in more than majority of scenarios there is a correct answer.

technically, Dave Man is correct if you choose to think of it that way, but to Goalie jerry, I only go from the input of the question. I can see how you think the question is indeterminate. it`s good to think outside the box and believe the answer is not given. But, it is a question because of basic grammar. and questions should and do have answers. I like thinking within the question and form based on just the input, to think there`s more input without the input can cause problems in math that is more or less not experimental. But, even if I am not correct, there is an answer to this question out there in this place. math goes very far, much further than many people know.

Wait, 0%. It`s a paradox. If you pick 25% you have a 50% chance of getting it right; if you pick either 50% or 60%, you have a 25% of getting it right.

@Mikeado, that isn`t funny. I actually had someone tell me that the chance of scoring a touchdown on a given play in football was 50% because either you do or you don`t score a touchdown. They could not be convinced they were wrong.

Those are the kind of people the lottery is made for.

Question is kinda faulty, if I choose an answer to a question with 4 options at RANDOM then what they actually say has no input so my odds are 1/4 of getting it right.

0%. Since two of the answers are the same there is technically only 3 options and you can only choose 1 option. Hence 1 out of 3, should be correct, but since .33 is not an option none of the answers are correct so you have no probability of choosing the right answer.

ould have been to add an answer E): 20%. This way you cause there to be 5 answers, meaning that if you randomly selected an answer from the five you would have a 1:5 chance of picking any one answer. 1:5=1/5=0.2=20%. So, 20% is the best answer I see for this problem, assuming you want to over think it like I did and force it to be within the parameters set by it being a multiple choice question. I apologize for the extended post; I am still new to having to limit characters in posts as I only recently became more active on the Internet. Moderators, please don’t delete it (them), I will do my best to make sure that this doesn’t happen again. Thanks. If you followed this logic all the way through, you don’t need glasses.

ldn`t be, truly, because it would contradict itself. If you were never right, then how could E) (0%) be a correct answer? As such, those who said that 0% is the right answer were only partially correct. While there is no correct answer as is, saying 0% is the right answer and should be there as E) would cause it to be a paradoxical answer, being wrong because it`s right (since there is no right answer, it’s correct, but by being correct it becomes the right answer, making it wrong) and right because it`s wrong (now that 0% has been determined to be wrong, it can be right again, bringing us back to the previous parenthetical phrase). Those who simply said 0%, without suggesting it be added as E), were really right, but not technically as correct as they could have been, considering how they`d simply dismissed the problem as unsolvable even with modification (which it isn’t) or simply didn`t think that far. The way I see it, the best way to alter and solve this problem w

If I chose an answer to the question in this image at random, assuming that I can only randomly choose one of the given answers A) through D), There would be no chance of my being correct; I would have a 0% chance. 0%, however, is not an option (this possibility will be addressed later), so this is an unsolvable question with the given choices. This will be shown presently:

A): Because 25% is listed as an option twice, meaning it occurs 50% of the time, randomly choosing an answer causes 25% to turn up 50% of the time. The answer here and in D) is 25%, not 50%. This answer is wrong.

B): The answer 50% only turns up once. Since there are 4 answers, it turns up 25% of the time. The answer B) is 50%, not 25%. This answer is also wrong.

C): This answer is wrong because none of the options turn up 60% of the time.

D): This answer is wrong for the same reason that A) was wrong.

Adding an answer E): 0%, would seem right, but in fact wou

It`s a paradox, no real solution. And no, it`s not 0% either. You run into a contradiction no matter which starting point (25% or 50%) you begin your reasoning with. in other words, the "right answer" is recursive onto itself, you need to "define the right answer to define the right answer".

- What percentage of I-A-Bers can answer this? You may now strap on your mind f*ck helmet.
Unless they`re all wrong. Oo;

Normally in 4 answer questions, you have a 25% chance of getting it right. However, because two of the answers is 25% then that answer becomes void.

So A and D are not the correct answer. You only have a 25% chance of choosing B and a 25% of choosing C. However, 50% is not the correct answer, and neither is 60%.

So you might think, "Oh, there is no correct answer listed here. So the answer must be 0%". And you`d be right. However, listing 0% as an option would change the answer to the question. As such, the possibility of guessing 0% would be more than 0%.

It`s a trick question with no answer. (But really the answer is 0%, unless the option of 0% is given).

the avarage results of guessing is roughly 50%

if you have a slight idea about said question, it is raised to 60%

then you take a probability calculator, give it a nice cup of hot tea.

and This is the defining factor. so the percentage becomes irrelevant becuase you are alway`s right. normality is now restored, anything you can`t cope with is therefore your own problem.

MrOrange, we gotta stop meeting on oposite sides of topics.

Answer - it`s a trick question.

You`d think 1 in 4 is 25% but A & D are 25% so that makes it 2 in 4 which is 50%. But B is 50% so we`re back to 1 in 4 or 25%.

Circular with no answer.

inb4 paradox: Not necessarily. It`s only a 25% of picking a correct answer if you assume true randomness to your distribution, so unless the answer is being picked by a process involving radioactive decay it is not truly random.

This question, that excludes averages.

The answers provided can be correct or can`t be. it`s your own insecurity that tells you that it can`t be and that there has to be a correct answer in which case you enter the paradox.

you are alway`s right. becuase there is no evidence to suggest you are wrong.

oh and Gerry1of1, if you look at yourself in a mirror, how many of you are there?

Dammit you are right. I had this whole retort ready but it kept falling apart.

Yeah it`s circular.

Incorrect, this is what happens to mathematicians after a night of heavy drinking.

Remember: "Don`t drink and derive".

You will always be wrong... not because the question doesn`t have an answer. Just because you`re a failure. Now drop your math class and go take gym again.

To make this easier, let`s just say that both A and D are considered correct, so the answer is B, 50%. Why? What`s the probability of choosing the correct answer out of 4 options? 25%. Consider that 25% shows up twice, so the answer has to be 50%, because you have a 50% chance of choosing either of the 25%`s.

No, Orange, it`s not insecurity on my part. If the question is the odds of getting it right, and the answer to that is zero, but zero is not an option, then it`s a trick question.

To answer your question - How many of "me" in the mirror... None, I`m a vampire.

if the answers provided to the question are not correct, it means you can`t answer the question with those answers so if i say that my answer is right, the answers provided can`t be used to say i am wrong becuase they are. hence i am right.

as long as you think that there is a right answer among the wrong answers you will be wrong.

if i look in a mirror, i can see two of me, but i know there is only one of me.

if take the sentence apart, This question,

that excludes others so averages do not count.

"if you choose an answer at random"

where does it say that i have to pick one of the below?

and that my opposing friend is the trick in the question.

There is nothing wrong with the above statement, you could only say that it is wrong becuase it claims to be true _until_ it is proofed _wrong_, which alows you to think it can be wrong but you can`t prove it is wrong hence it is alway`s true.

it`s a linguistic paradox which holds no meaning other then what you give it. if you think it can be wrong, you will search in vain for that argument and you enter the paradox, accept that it is true and you do not.

MrOrange "and that my opposing friend is the trick in the question."

Told`ya it was a trick question. But it`s taken you 4 posts and a dozen paragraphs proving me wrong before you agreed with my conclusion.

Brevity - get some.

The answer can never be B, or C. There is only 1 correct answer and 4 choices, 2 25%s choices are still individual answers.. the person picking at random will ONLY pick 1 answer.. and ONLY has a 25% chance.... 1 of the 4 answer is correct, not 2. The trickery is for you the person reading and not picking picking at random.

Theres a complex solution for it, but thats the right answer regardless.

Without consideration to the answers provided and selecting randomly, the correct answer is 25%.

Since this test cheats and offers the 25% value twice, the answer may seem as though it would be 50%. If it were 50%, then the odds of picking 50% are 25% STILL.

So 25% is there twice, 50% chance of picking 25%, plus the chance of picking 50%, which makes 3 of the answers correct.

75% chance of picking A right answer, which is not on the test, therefore the odds of finding the correct answer of 75% is non existant, and thus the correct answer is 0%!

NEVER GO IN AGAINST A SCICILIAN, WHEN DEATH IS ON THE LINE! Hahaha, hahaha, haha.....*dead*

my reasons, the human mind

there is a greater probability that when someone doesnt know a multiple choice answer they go for C.

or will go for one of the middle answers

very very rarely do people pick the 2 outer answers.

theere is a very old psychological trick where if u ask someone to just think of a number between 1-10 60% of people will pick the number 7. people tend to think the outer edge answers are too obvious so in trying not to fit in with the "regular" people they go for what they beleive to be an obscure number when in actual fact they are following the crowd they so desperatly want to get away from.

to sum up

mathematically its either A or D - 25%

but psychologically its more like C- 60%

Chance of rain in the Sahara desert...50%

Chance you`ll die being struck by a meteor...50%

Chance you`ll be impregnated by an extra-terrestrial and give birth to a child who will become the President in 50 years...50%

@gerry1of1 Brief enough for ya?

the probability that you pick the right answer is 1/4, so the answer is 25% since there are two correct answers the chance is 50%

thats the probabilty side of it, otherwise you come to the philosophical side of it which bring you to my previous post but appearantly they are to long.

Take that one more step:

The probability that you pick the right answer is 1/4, so the answer is 25% since there are two correct answers the chance is 50%. But the correct answer of 50% only appears once (i.e. 25% of the time) so the correct answer is 25%, but the correct answer of 25% appears twice (i.e. 50% of the time) so the correct answer is 50%, but the correct answer of....Ad infinitum.

"The chance you are correct is 0%

Reason:

*When choosing answer A, you assume 25% to be correct.

This means B and C are not correct and D is correct too.

Thus, the correct answer would be 50%.

This means A is not a correct answer

*Same logic applies to answer D.

This means D is not a correct answer.

*When choosing answer B, you assume 50% to be correct.

This means A,C and D are not correct.

Thus the correct answer would be 25%.

This means B is not a correct answer.

*When choosing answer C, you assume 60% to be correct.

This means A, B and D are not correct.

Thus the correct answer would be 25%

This means C is not a correct answer.

** In summary none of the answers is correct.

So the chance you will be correct is 4* 1/4 * 0 = 0%

JUST A QUESTION OF LOGIC

THIS POst should not be on IAB, as it isn`t boring at all!!

So even though the probability is 25%, the answer is any of the 4

that is stupid, one of the answers has to be correct, and the probability of each of them is 1/4th of being correct all the time

Take one step less. "if you choose an answer at random"

leads you to 1/4 or 25%.

"what is the _chance_ of picking the right answer"

since 25% percent is present twice, it`s a 50% chance of picking the right answer at random.

As said before the trick is not in the mathmatics, but in the linquistics.

But B isn`t the right answer.

nope, you are asked what the chance of being correct is

so ... the probability is 1/4, your chances of picking that answer is 2/4 and thus 50%

but, what is the function of the comma in grammer?

if this definition is "Use a comma to separate the elements in a series (three or more things)"

then do we get closer to reaching an understanding of the question asked?

if we can agree on the question asked then we could perhaps also agree on a solution.

@gerry1of1 See what i mean with:

The answers provided can be correct or can`t be. it`s your own insecurity that tells you that it can`t be and that there has to be a correct answer in which case you enter the paradox.

you are alway`s right. becuase there is no evidence to suggest you are wrong.

there is an probability and a chance of a right answer, and a probabilty of a wrong answer,

the question can be answered in more way`s then 1, both on the linguistic side and on the mathmetical side, which means that there is a probability of a right answer, the chances of being proved wrong are irrelevant.

if we each build the exact same wooden house,

and we need calculate our sawcut, you could work out the probability of bieng wrong.

i could assume i was right, err, on the positive side, make my cut, if lucky it fits if not i cut again, but my house will be ready, whilst your paradoxal excursions

You DO realize, of course, is that basic argument is "50% is the correct answer because the correct answer is 25%"?

You have 50% chance to pick 25%

you have 25% chance to pick 50%

you have 25% chance to pick 60%

The correct answer must be the one in which your % chance of picking it matches its declared value.

None of those answers match the actual % chance you have to pick an answer, hence the answer is 0.

@Jendrian "one of the answers has to be correct" ~ this is where you failed.

I guess..

The answer is *UNDEFINED*. Zero is a definate answer, but quite simply one cannot know what the "question" is.

This is not a question that can be answered. Ignore the multiple choices - nothing in the prompt limits you to these four choices. The question has no answer that can be determined with logic.

This is non-sensical. It is not even a paradox. It is like asking "How many flerpas do dipady triznos?" *UNDEFINED*

Correct Answer.... "A or D" :)

Why do you assume that? What in the question limits your choices to those listed? Everyone is conditioned to see A, B, C, D and assume one is the answer. That is the mistake. You are all reading too much into it - I did it to. "Well, if I choose A, there are two so its 50%, so can`t be A, or D, or, um, B...hmmm."

The multiple choice selections are irrelevant and meaningless - again, why only choose those? - tricking you into looking for meaning in them.

See, there actually is no "question." This is more philosophical than logical. What is the right answer? There COULD be a "question" in the mind of the author, and there is some small chance you could randomly choose the answer from the ether, but you simply cannot deduce the probability based on the information given.

The answer is *UNDEFINED*.

What limits you to only those four choices? Too many assumptions that the answer is in front of you. It doesn`t say "choose from below," or "choose from one of these."

It is a trick. You cannot answer the question - thus the answer cannot be 0%, because that is a certain answer. The answer is undefined. Even if there is a correct answer, it is unknowable.

if you choose (A or D), you actually Get B(50%) and if you choose B you actually get (A or D)(25%). The proof using really big numbers in C#...

char[] answer = {`a`, `b`, `c`, `d`};

int i = 0;

int count = 0;

Random r = new Random();

char guess = `f`;

for (i = 0; i < 10000000; i++)

{

guess = answer;

if( guess == `b`)

count++;

guess = `f`;

}

Console.Write(count);

Console.Read();

if (guess = `B`) you get 25% of the time

if (guess = `a` || guess = `d`) you get 50%

which blew my mind!!!

Written in C#.

In a nut shell.

When you select 50% it only appears in 25% of the choices.

Yet when you select 25% it appears in 50% of the choices.

Hot dang, who ever wrote this is a gosh dang Houdini!!!

a.) 50%

b.) 25%

c.) doesn`t matter

d.) 50%

Now

50% appears 50% of the time, not 25%

and

25% appears 25% of the time, not 50%,

But now

if you choose 25% it will be correct

and

if you choose 50% it will still be correct.

Now this blows my mind even more because it is still a paradox. :|

It seems everybody was correct...

Those are the kind of people the lottery is made for.

No, those are the kind of people a shot to the head is made for.

creating your own choice is the only answer

A): Because 25% is listed as an option twice, meaning it occurs 50% of the time, randomly choosing an answer causes 25% to turn up 50% of the time. The answer here and in D) is 25%, not 50%. This answer is wrong.

B): The answer 50% only turns up once. Since there are 4 answers, it turns up 25% of the time. The answer B) is 50%, not 25%. This answer is also wrong.

C): This answer is wrong because none of the options turn up 60% of the time.

D): This answer is wrong for the same reason that A) was wrong.

Adding an answer E): 0%, would seem right, but in fact wou

I was tricked.