and Dextrine it is almost correct, if you use U substitution to do the integral, you let U =2x and du = 2dx which becomes dx = 1/2 du, and then the rest is obvious. (if you`ve done calc)

Of course it`s easier just to remember Integral Cos(nx)dx = 1/n Sin(nx). The negative sign should not be there, and since the integral is not bounded there should be a constant added to it.

Dats how we roll, where of course the diameter of the wheel is given by 2(pi)R... Actually, the diameter would just be 2R. You`re thinking of the circumference.

And yes, it should be + 0.5 sin (2x) + C.

Would be funny if someone corrected it with red spraypaint, and a bit in the corner saying "see mee after class".

@42467 no, that`s calculus, it`s integration It is integration of a trigonometric function, but it`s still calculus. It`s the approximation of the area bounded by a curve between two limits (in this case unspecified limits) using a summation of the areas of an infinite number of infinitely thin rectangles of height f(x) and width dx for every single x between a and b, which is calculus.

- Trigonometry, bitch.
+C!!!!!!!!!!

That gives you the circumference.

I expected as much from some hoodlum.

d(-sin(2x)/2)/dx = -cos(2x)

the derivative of cos is -sin, but the integral of cos is sin

Of course it`s easier just to remember Integral Cos(nx)dx = 1/n Sin(nx). The negative sign should not be there, and since the integral is not bounded there should be a constant added to it.

Actually, the diameter would just be 2R. You`re thinking of the circumference.

And yes, it should be + 0.5 sin (2x) + C.

Would be funny if someone corrected it with red spraypaint, and a bit in the corner saying "see mee after class".

c:-|s(x) := -cos(x) ?

Scary!

Calculus actually. And he forgot `+c`.

What a noob :D

Also, this is Calculus.

he forgot more than just +C, the INTEGRAL of cos is positive, the derivative is negative

...bitch.

And good catch SkyeDragon!

We fight these guys all the time. We go all zero divided by infinity on they ass yo.

Oh integration, how I hate you...

no, that`s calculus, it`s integration

It is integration of a trigonometric function, but it`s still calculus. It`s the approximation of the area bounded by a curve between two limits (in this case unspecified limits) using a summation of the areas of an infinite number of infinitely thin rectangles of height f(x) and width dx for every single x between a and b, which is calculus.

And yes. I created an account just to vent my calculus-rage here.

You`ll do well here.

<3

2) I don`t see limits to the integrand, so where`s the drating constant, n00blet?