Trigonometry, bitch.

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Trigonometry, bitch.

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2) I don`t see limits to the integrand, so where`s the drating constant, n00blet?

<3

You`ll do well here.

And yes. I created an account just to vent my calculus-rage here.

no, that`s calculus, it`s integration

It is integration of a trigonometric function, but it`s still calculus. It`s the approximation of the area bounded by a curve between two limits (in this case unspecified limits) using a summation of the areas of an infinite number of infinitely thin rectangles of height f(x) and width dx for every single x between a and b, which is calculus.

Oh integration, how I hate you...

We fight these guys all the time. We go all zero divided by infinity on they ass yo.

And good catch SkyeDragon!

...bitch.

he forgot more than just +C, the INTEGRAL of cos is positive, the derivative is negative

Also, this is Calculus.

Calculus actually. And he forgot `+c`.

What a noob :D

Scary!

c:-|s(x) := -cos(x) ?

Actually, the diameter would just be 2R. You`re thinking of the circumference.

And yes, it should be + 0.5 sin (2x) + C.

Would be funny if someone corrected it with red spraypaint, and a bit in the corner saying "see mee after class".

Of course it`s easier just to remember Integral Cos(nx)dx = 1/n Sin(nx). The negative sign should not be there, and since the integral is not bounded there should be a constant added to it.

d(-sin(2x)/2)/dx = -cos(2x)

the derivative of cos is -sin, but the integral of cos is sin

I expected as much from some hoodlum.

That gives you the circumference.

+C!!!!!!!!!!

- Trigonometry, bitch.