He might fail math in school, but like that other kid from earlier this week, he"s got a bright future in porn.

Log in with a social network:

He might fail math in school, but like that other kid from earlier this week, he"s got a bright future in porn.

The Trending 10

- WEEK
- MONTH
- YEAR

257,869

483

.......NEEEEEEEEEERRDSSSSSS!!!!!!!!

s = r{theta} = 4pi ~ 12.5663706 cm.

i know that your previous result is in term of unit circle and disregard what you think a unit circle is, the formula is still wrong.

First, what do you think is the area of the triangle ?

Second, add your result with 0.5*pi*(4)^2, corresponds to the area of 3 pieces of the circle.

Do you get the area of the triangle ?

Yes it does, it`s a ratio of the unit area. I can`t read those dimensions - what is that, 8cm? So pi * r^2 gives us 50.265cm^2, and 0.0931 of that would be 4.68cm^2.

Damn you photoshop! "

It is referring to the triangle.

Damn you photoshop!

lol no obviously the area depends on the radius of the circles. Besides your formula doesn`t make any sense in this case.

No, 1 - (pi/12^-2)

@duffytoler lol Shaded area = (sqrt3/pi - 1/2)*r^2* (area of unit circle)

Pie?! Lets eat!

Each circle has a radius of 4 cm. Each angle of an equilateral triangle is 60 degrees. Circles have 360 degrees.

60/360 = 1/6 * circumference

C = pi* diameter

1/6 * (pi * diameter) = 1/6 * (8picm) = (4pi)/3 cm.

One side of the triangle is (4pi)/3 cm. So all 3 sides, i.e., the perimeter, is (4pi)/3 cm * 3 =

4 pi cm.

It`s a woman`s butt with a string.

Not exactly brain surgery is it?

I`d personally see it as 3*arclength, then it becomes easy to think about.

Each angle of the triangle is 60 degrees, or 1/6 the perimiter of the circle (60/360 = 1/6)

1/6 * PI*R1 + 1/6 * PI*R2 + 1/6 * PI*R3. Still since R1 = R2 = R3, it comes out to C(any)/2.

The units should not be centimetres squared - they`re looking for a perimiter, not an area.

[quote]Majored in applied mathematics.[/quote]

Well that`s disappointing and a poor reflection on your degree, because you should then realise that CJ`s solution is correct.

The three arcs that make up the perimiter of the shaded area are parts of the circumferences of circles with centres at the vertices of the equilateral triangle.

There`s no circle.

It`s an equilateral triangle.

They give you one side.

- He might fail math in school, but like that other kid from earlier this week, he`s got a bright future in porn.