OK the 1,3,10,27 combo doesn`t work for me. I tried it a few times and get numbers like 34 and 19 and 18 that you can`t add up to exactly with the 4 in the combo.

I`m either not getting the concept, getting screwed by the game, or I`m just a moron.

The 1,3,10,27 combo doesn`t work all the time. The problem comes about with numbers like 5, there`s no way to do it. My guess is you just got lucky.

Here`s how you would go about doing it without looking on forums and without looking at the hint:

1) Divide your target number into 3 groups, if you have 1 left over, adjust the middle group so it`s 1 bigger, if you have 2 left over, adjust the first and last group:

The resultant set={1-13,14-27,28-40}

The top bound of the middle group is one of your numbers: 27

Now find 3 numbers, which in some combination, form every number of the first group. Your answer is then: Group 1: combo of first 3 numbers (comboFirst3) Group 2: (upper bound for mid) - (comboFirst3) Group 3: (upper bound for mid) + (comboFirst3)

So for using 27 as your anchor, any 3 numbers that can add up to any number between 1-13 works. 1,3,9 works

- Balance the weight with as few already used weights as possible. Good at math in your head?
1,3,10,27

Shame I can;t get on the high score board. Since its already full of 1000`s.

(And Woo. First post btw :D)

Is that good or bad??

Perfect score 1000

#16 CJ - IAB

1,3,10,27 combo

seems to work all the time.

Is this good?

y/n

I`m either not getting the concept, getting screwed by the game, or I`m just a moron.

1,3,9,27

Well, I THOUGHT I was until I played this...

You just have to remember you can put weights on both sides of the scales.

Here`s how you would go about doing it without looking on forums and without looking at the hint:

1) Divide your target number into 3 groups, if you have 1 left over, adjust the middle group so it`s 1 bigger, if you have 2 left over, adjust the first and last group:

The resultant set={1-13,14-27,28-40}

The top bound of the middle group is one of your numbers: 27

Now find 3 numbers, which in some combination, form every number of the first group. Your answer is then:

Group 1: combo of first 3 numbers (comboFirst3)

Group 2: (upper bound for mid) - (comboFirst3)

Group 3: (upper bound for mid) + (comboFirst3)

So for using 27 as your anchor, any 3 numbers that can add up to any number between 1-13 works.

1,3,9 works

all you do is take the same number on the side to balance it out.