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#3 is the Fibonacci Sequence in sheep`s clothing. Although the reason it`s arranged like that escapes me at the moment, I know that the numbers in the next line must add up to 13.

1 11 (there is ONE 1 in the above line; one 1 = 11) 21 (there are TWO 1`s in the above line; two 1 = 21) 1211 (etc) 111221 So the next line is 312211. 3+1+2+2+1+1=10

also i was using the same pattern of just ones and twos and building a number consisting of ones and twos whose sum and length is exponentially larger than the previous line. which is where i think someone?`s solution doesn`t make sense to me.

On 9/26/2004 4:36:20 PM gizmo331 wrote: also i was using the same pattern of just ones and twos and building a number consisting of ones and twos whose sum and length is exponentially larger than the previous line. which is where i think someone?`s solution doesn`t make sense to me. 1) Your answer didn`t work because it didn`t account for the number and placement of 1s and 2s. 2) The Fibonacci sequence is not exponential. Neither was the sequence of line lengths in this problem.

- Can you pass? The green on white is kinda hard to read.:-)

I know question 3 :D

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What?

It actually adds up to 10. Here`s how it works:

1

11 (there is ONE 1 in the above line; one 1 = 11)

21 (there are TWO 1`s in the above line; two 1 = 21)

1211 (etc)

111221

So the next line is 312211. 3+1+2+2+1+1=10

only one answer fits it the way I`ve described it (since 5+8 =/= 10), but your way also works.

Wear your damn seatbelts bitches

Its not Googles fault.

1) Your answer didn`t work because it didn`t account for the number and placement of 1s and 2s.

2) The Fibonacci sequence is not exponential. Neither was the sequence of line lengths in this problem.